Jack has 20 sweets. Will also has 20 sweets. Jack gives Will x sweets. Jack then eats 5 of his sweets. Will then eats half of his sweets. Write expressions for the number of sweets Jack and Will now have.

They both start with 20 sweets. To get the total number of sweets that Jack has, you need to take away x because that is the amount that he gives to will. Jack then eats 5 of his sweets so you need to take away 5 from 20-x. you do not know the value of x, but you can take the 5 from the 20 to get 15. Therefore Jack has 15 - X sweets at the end.Will, however, gains the x number of sweets that Jack gives him, so you ADD x on to his initial 20. However, will then eats half of his sweets after Jack has given him the additional x, so you divide the total amount (20 + x) by 2.

Answered by Lucy M. Maths tutor

4029 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify fully 3(3 – x) – 2(x – 4)


How to do simultaneous equations?


Simplify fully 3/(2x + 12) - (x - 15)/(x^2 - 2x - 48)


A particle P of mass 0.4 kg is moving under the action of a constant force F newtons. Initially the velocity of P is (6i – 27j) m s−1 and 4 s later the velocity of P is (−14i + 21j) m s−1 . Find, in terms of i and j, the acceleration of P.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences