A ball is thrown downwards from a height of 10m with speed of 5m/s, assuming g=10m/s^2, calculate the final velocity of the ball when it hits the ground

First recall the suvat equation: v^2=u^2+2as.
It is always handy to draw a diagram in physics to illustrate the problem.
Next, using u=5, a=10, s = 10, solve for v in the suvat equation, arriving at the final answer of v=15m/s

Answered by Sachin V. Physics tutor

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