g(x) = e^(x-1) + x - 6 Show that the equation g(x) = 0 can be written as x = ln(6 - x) + 1, where x<6
0 = ex-1+ x - 6 ex-1 = 6-x x-1 = ln (6-x) -> here we have taken the natural log of both sides, but it only shows on one side as the natural log of e is 1.x = ln (6-x) + 1Question taken from Edexcel 2013 C3 past paper, with my own adapted answer.
SN
Related Maths A Level answers
All answers ▸The General Form of the equation of a circle is x^2 + y^2 + 2gx +2fy + c = 0. Find the centre of the circle and the radius of the circle in terms of g f and c.
find the integral of 1+3 root x
How do you go about differentiating a^x functions?
Explain the chain rule of differentiation