What is the stress in a cylindrical rod of 10.0cm diameter when loaded by 50.0N force at each end?
Stress = Force/Area and cross sectional area of a cyclinder = pi.r2
As diameter = 10.0cm=0.1m r=0.05m so area = 3.14*0.052 = 0.00785m2
As the force is 50.0N the stress is 50/0.00785=6369Nm-2or 6.37kPa to 3 significant figures
