Write 156 as a product of its prime factors.

Before we begin to answer this question we need to have a clear idea of what a prime number is: A prime number is a number greater than 1 that cannot be found by multiplying 2 smaller numbers. To answer this question we need to keep dividing by the lowest possible prime factor that gives a whole number as a result. It maybe sounds a little dense in words, lets look at the question. The lowest prime factor for 156 is 2: 156/2= 78. We can divide by 2 again: 78/2=39. Now we can't divide by 2 anymore, lets try 3: 39/3= 13. 13 is already a prime number telling us we can't go any further. So 156 written as a product of its prime factors is: 22 x 3 x 13

Answered by Alexander A. Maths tutor

12545 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you multiply two brackets with two terms in them? For example (2x-3)(x+4)


Line L1 passes through points (4,6) and (12,2). Line L2 passes through the origin and has gradient -3. The two lines intersect at point P. Find the co-ordinates of P.


Factorise x^2 + 2x – 15


The nth term of a sequence is 7n-4. Write down the 4th term and the 10th term of the sequence. The first four terms of a different sequence are 9, 13, 17, 21. Find an expression for the nth term of this sequence.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences