The Curve C has equation y = 3x^4 - 8x^3 - 3. Find dy/dx.

The question is asking us to differentiate the equation y = 3x^4 - 8x^3 - 3. To differentiate this equation, we must differentiate term-by-term. In order to differentiate a term, we must multiply the coefficient of the x-term by the power that the x-term is raised to and then reduce the power by one.
So lets begin by differentiating the term 3x^4. We multiply the coefficient (3) by the power that the x is raised to (4) and then reduce the power of the x by 1. Thus when we differentiate 3x^4, we get 12x^3. Similarly, lets differentiate the next term, -8x^3. We multiply the coefficient (-8) by the power of x (3) and then reduce the power of x by one. Hence, differentiating -8x^3 gives us -24x^2. The last term (-3) is a constant. When we differentiate constants, we always get zero as there is no x-term present. So differentiating -3 gives us 0. By grouping each differentiated term, the answer to our question is dy/dx = 12x^3 -24x^2.

Answered by Dharmik C. Maths tutor

5308 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

write the vector equation of a line passing through (1,-1,2) and (2,2,2).


Show that x^2 - 8x +17 <0 for all real values of x


A curve, C, has equation y =(2x-3)^5. A point, P, lies on C at (w,-32). Find the value of w and the equation of the tangent of C at point, P in the form y =mx+c.


Differentiate the function f(x) = sin(x)/(x^2 +1) , giving your answer in the form of a single fraction. Is x=0 a stationary point of this curve?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences