Given the points (6,6) and (10,8) calculate the gradient of the line passing through them and the point at which it intersects the y-axis?

To find the gradient use the formula:m = (y2-y1)/(x2-x1)Plug in values:m = (8-6)/(10-6) = 1/2Hence gradient = 1/2--Now using the equation for a line y = mx+c and point (10,8)8 = 1/2*10 + cc = 3Hence when the line passes through the x axis, x = 0 and y = c and hence values is 3

GA
Answered by Gilad A. Maths tutor

3413 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise 9a^2+6ab.


Find the equation of the line that passes through the (4,6) and (9,-4)


A linear sequence begins: a + 2b, a + 6b, a + 10b, ..., ... Given that the 2nd term has a value of 8 and the 5th term has a value of 44, calculate the values for a and b


Please factorise and solve x^2 -1 = 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences