Given the points (6,6) and (10,8) calculate the gradient of the line passing through them and the point at which it intersects the y-axis?

To find the gradient use the formula:m = (y2-y1)/(x2-x1)Plug in values:m = (8-6)/(10-6) = 1/2Hence gradient = 1/2--Now using the equation for a line y = mx+c and point (10,8)8 = 1/2*10 + cc = 3Hence when the line passes through the x axis, x = 0 and y = c and hence values is 3

GA
Answered by Gilad A. Maths tutor

3877 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve algebraically for a and b: 6a+b=16, 5a-2b=19


(given a graph with a straight line and 2 labelled points) Find the equation of the line.


What is solution by substitution?


How could you sketch a graph for y=x^2-10x+21?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning