Calculate the pH of the following solutions: 0.002 mol/dm^-3 KOH

pH by definition is given as -log₁₀(c_H+) or log₁₀(1/c_H+), where c_H+ is the concentration of the H+ ions in the solution.Similarly, pOH= -log₁₀(c_OH-) pH + pOH= 14KOH is basic so we can calculate the pOH, which is pOH= -log₁₀(c_OH-)=-log₁₀(0.002)= 2.69pH=14-2.69=11.31