Calculate the pH of the following solutions: 0.002 mol/dm^-3 KOH
pH by definition is given as -log10(cH+) or log10(1/cH+), where cH+ is the concentration of the H+ ions in the solution.Similarly, pOH= -log10(cOH-) pH + pOH= 14KOH is basic so we can calculate the pOH, which is pOH= -log10(cOH-)=-log10(0.002)= 2.69pH=14-2.69=11.31
CB
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