Solve the simultaneous equations 3x + 2y = 12 and 10y = 7x + 16

First we need to rearrange both equations into the form ax + by = c (where a, b and c are the integers). We can label these 1. and 2.We then have:3x + 2y = 12 1.7x -10y = -16 2.In order to find the x value, we need to get rid of the ys. This can be done by multiplying the first equation by 5. This gives us 15x + 10y = 60. 3. We can now easily work with equations 2. and 3. as the y values have the same coefficients.15x + 10y = 60 3.7x - 10y = -16 2.In order to get rid of the y values, we need to add the two equations together (because 10y + (-10y) = 0 )This leaves us with:22x = 44x = 2We can now substitute x = 2 back into equation 1. to find y(3 x 2) + 2y = 122y = 6y =3 Just to be sure, substitute x and y into equation 2. (7 x 2) - (10 x 3) does equal -16. Therefore, the solutions are x= 2 and y=3

Answered by Anjali A. Maths tutor

3467 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

f(x) = 3x - 2a || g(x) = 2ax + 1 || fg(x) = 2x + b/2


There are 720 boys and 700 girls in a school. The probability that a boy chosen at random studies French is 2/3 The probability that a girl chosen at random studies French is 3/5. Work out the number of students in the school who study French.


How to differentiate 9x^2+ 4x-7=0


Solve the simultaneous equations : x ^2+2y=9, y=x+3 to find solutions for x and y.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences