Compute the derivative of arcsin(x).

To compute the derivative of arcsin(x) we use the fact that it is the inverse of sine. Write y=arcsin(x). We want dy/dx. Taking sin on both sides yields sin(y)=x. Use implicit differentiation to differentiate both sides with respect to x. We obtain cos(y)*(dy/dx)=1 --> dy/dx=1/cos(y). Now sin(y)=x and we have the pythagorean identity sin^2(y)+cos^2(y)=1. This gives cos^2(y)=1-sin^2(y)=1-x^2 and so cos(y)=sqrt(1-x^2) (reason for choosing +sign is that cos(y)>0 on range of y=arcsin(x)). Thus dy/dx=1/sqrt(1-x^2). So derivative of arcsin(x) is 1/sqrt(1-x^2).

JP

Related Further Mathematics A Level answers

All answers ▸

The curve C has polar equation 'r = 3a(1 + cos(x)). The tangent to C at point A is parallel to the initial line. Find the co-ordinates of A. 0<x<pi


Given that the equation x^2 - 2x + 2 = 0 has roots A and B, find the values A + B, and A * B.


Find the general solution to the differential equation y'' + 4y' + 3y = 6e^(2x) [where y' is dy/dx and y'' is d^2 y/ dx^2]


Two planes have eqns r.(3i – 4j + 2k) = 5 and r = λ (2i + j + 5k) + μ(i – j – 2k), where λ and μ are scalar parameters. Find the acute angle between the planes, giving your answer to the nearest degree.