Compute the derivative of arcsin(x).

To compute the derivative of arcsin(x) we use the fact that it is the inverse of sine. Write y=arcsin(x). We want dy/dx. Taking sin on both sides yields sin(y)=x. Use implicit differentiation to differentiate both sides with respect to x. We obtain cos(y)*(dy/dx)=1 --> dy/dx=1/cos(y). Now sin(y)=x and we have the pythagorean identity sin^2(y)+cos^2(y)=1. This gives cos^2(y)=1-sin^2(y)=1-x^2 and so cos(y)=sqrt(1-x^2) (reason for choosing +sign is that cos(y)>0 on range of y=arcsin(x)). Thus dy/dx=1/sqrt(1-x^2). So derivative of arcsin(x) is 1/sqrt(1-x^2).

Related Further Mathematics A Level answers

All answers ▸

Using de Moivre's theorem demonstrate that "sin6x+sin2x(16(sinx)^4-16(sinx)^2+3)"


How do I construct a proof by induction?


In statistics, what is the benefit of taking a sample survey rather than a census?


A particle is moving in a straight line with simple harmonic motion. The period of the motion is (3pi/5)seconds and the amplitude is 0.4metres. Calculate the maximum speed of the particle.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences