The curve C has the equation ye ^(–2x) = 2x + y^2 . Find dy/dx in terms of x and y.


differentiate both side with respect to x : (dy/dx)e^(-2x)+y(-2e^(-2x)) = 2+2y(dy/dx)
rearrange it : (-2y+e^(-2x))(dy/dy) = 2 + 2ye^(-2x) ==> dy/dx = ( 2 + 2ye^(-2x) ) / ( -2y+e^(-2x) )

JC
Answered by Jimmy C. Maths tutor

5505 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the general solution to the differential equation '' (x^2 + 3x - 1) dy/dx = (2x + 3)y ''


Differentiate y = 2xln(x)


differentiate y = (4-x)^2


If the functions f and g are defined: f: x--> x/5 + 4 g : x--> 30x + 10. what is x, if fg(x) = x. ?? What would fgf(x) = x^2 be??


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning