How do I solve the equation x^2 + 6 = -5x

This equation is an example of a quadratic equation, which is noticeable by the presence of the x2 term on the left hand side. We begin to solve these types of equations by moving all the terms to one side (often referred to as making the equation equal zero). This leaves us with x2 + 5x + 6 = 0. Solving quadratics in this form is done by factorising the equation into two separate brackets (which could be expanded to give the equation we started with. Now in order to do this we have to find two numbers which add up to 5 (for the 5x) and times to make 6 (for the +6). This is the same process we use for all quadratics you'll come across in this form. Those number are in this case 3 and 2 (2+3=5 , 2x3=6). We now write the equation out with these numbers in the brackets as follows; (x + 3)(x +2) = 0. In order for this equation to equal 0, either of the brackets must do so, therefore x must equal either -3 or -2 so the solution is x = -2 , -3.

Answered by Viktor A. Maths tutor

3816 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 3y^2 – 60y + 220 = 0 using the quadratic formula:


Write 2x^2 + 16x + 26 in the form a(x + d)^2 + e where a, d, and e are integers.


Simplify: y+y-x×x


A square, with sides of length x cm, is inside a circle. Each vertex of the square is on the circumference of the circle. The area of the circle is 49 cm^2. Work out the value of x. Give your answer correct to 3 significant figures.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences