On a see-saw Mary, weight 600N balances John, weight 200N when she sits 1.5m away from the pivot. How far from the pivot is John?

Using the knowledge that the moments are balanced, we can create an equation to calculate the distance John is from the pivot:

600N1.50m = 200N(distance)
(600/200)*1.5 = distance
distance = 4.5m

AN
Answered by Alexander N. Physics tutor

11398 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is terminal velocity and what causes it?


Describe how you could find the density of a cube of metal? (4 marks) (Example from GCSE bitesize)


How fast are geostationary satellites moving?


What can the nucleus emit during radioactive decay?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences