On a see-saw Mary, weight 600N balances John, weight 200N when she sits 1.5m away from the pivot. How far from the pivot is John?

Using the knowledge that the moments are balanced, we can create an equation to calculate the distance John is from the pivot:

600N1.50m = 200N(distance)
(600/200)*1.5 = distance
distance = 4.5m

AN
Answered by Alexander N. Physics tutor

11112 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

A car's speed changes from 10m\s to 40m\s in 10 seconds. What is its acceleration?


A student has loaded a spring beyond its limit of proportionality. What does this mean?


When should you use the SUVAT equations?


The time taken for a wave to pass a point is 2.5 seconds. What is the frequency of the wave?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences