Find the first three terms of the binomial expansion of (3 + 6x)^(1/2).

To find the binomial expansion of this expression we need to use a formula. The formula states that for expressions of (1 + x)n it can be written as: 1 + nx + (n(n-1)x2)/2 ...
As our initial expression does not contain a "1" we need to manipulate it first. Remove a factor of 3 from our expression, taking care to keep the power the same, giving " 31/2(1 + 2x)1/2 ". From here we can substitute in our values, to give a binomial expansion of 31/2(1 + x - x/2). This can further be simplified by bringing the factor back into the bracket.

BW
Answered by Brendan W. Maths tutor

6634 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that y=ln([2x-1/2x=1]^1/2) , show that dy/dx= (1/2x-1)-(1/2x+1)


Find the area under the curve y = (4x^3) + (9x^2) - 2x + 7 between x=0 and x=2


Integrate x*ln(x)


solve the differential equation dy/dx = 6xy^2 given that y = 1 when x = 2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning