Find the first three terms of the binomial expansion of (3 + 6x)^(1/2).

To find the binomial expansion of this expression we need to use a formula. The formula states that for expressions of (1 + x)ⁿ it can be written as: 1 + nx + (n(n-1)x²)/2 ...
As our initial expression does not contain a "1" we need to manipulate it first. Remove a factor of 3 from our expression, taking care to keep the power the same, giving " 3^1/2(1 + 2x)^1/2 ". From here we can substitute in our values, to give a binomial expansion of 3^1/2(1 + x - x/2). This can further be simplified by bringing the factor back into the bracket.