Find the first three terms of the binomial expansion of (3 + 6x)^(1/2).

To find the binomial expansion of this expression we need to use a formula. The formula states that for expressions of (1 + x)n it can be written as: 1 + nx + (n(n-1)x2)/2 ...
As our initial expression does not contain a "1" we need to manipulate it first. Remove a factor of 3 from our expression, taking care to keep the power the same, giving " 31/2(1 + 2x)1/2 ". From here we can substitute in our values, to give a binomial expansion of 31/2(1 + x - x/2). This can further be simplified by bringing the factor back into the bracket.

BW

Related Maths A Level answers

All answers ▸

How do I find the equation of the tangent of a curve at a specific point.


Differentiate x^(4) + x^(1/2) + 3x^(5)


Differentiate expressions of form Ax^b where A and b are constants and x is a variable


Express 8/((root3) -1)) in the form a(root3) +b, where a and b are integers.