A curve is defined by the parametric equations; x=(t-1)^3, y=3t-8/(t^2), t~=0. Find dy/dx in terms of t.
dy/dx=(dy/dt)*(dt/dx); dy/dt=3+16t-3; dx/dt=3(t-1)2; dt/dx=1/3(t-1)2; dy/dx=(3+16t-3)/3(t-1)2
dy/dx=(dy/dt)*(dt/dx); dy/dt=3+16t-3; dx/dt=3(t-1)2; dt/dx=1/3(t-1)2; dy/dx=(3+16t-3)/3(t-1)2
