Answers>Maths>A Level>Article

Solve the simultaneous equations: y - 3x + 2 = 0 y^2 - x - 6x^2 = 0

y = 3x -2(3x-2)² - x - 6x² = 0 9x²- 12x + 4 - x - 6x² = 03x² - 13x + 4 = 0(3x - 1)(x-4) = 0 x = 1/3 or x = 4then y = -1 when x = 1/3 and y = 10 for x = 4

Answered by Katy D. • Maths tutor

9157 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the equation of the normal line at the point H, where θ= π/6, on the curve with equations x=3sinθ and y=5cosθ

Why is the differential of a constant zero?

Show that the derivative of tan(x) is sec^2(x), where sec(x) is defined as 1/cos(x). [Hint: think of tan(x) as a quotient of two related functions and apply the appropriate identity]

Solve the simultaneous equations: y - 3x + 2 = 0 y^2 - x - 6x^2 = 0

Related Maths A Level answers

Find the equation of the normal line at the point H, where θ= π/6, on the curve with equations x=3sinθ and y=5cosθ

Why is the differential of a constant zero?

Show that the derivative of tan(x) is sec^2(x), where sec(x) is defined as 1/cos(x). [Hint: think of tan(x) as a quotient of two related functions and apply the appropriate identity]

Given a quadratic equation, how do I find the coordinates of the stationary point?

We're here to help

Company Information

Popular Requests

© MyTutorWeb Ltd 2013–2025

CLICK CEOP