Show that the line with equation ax + by + c = 0 has gradient -a/b and cuts the y axis at -c/b?

This question involves inspecting the answers that have been provided to us. We have been given a constant gradient, and a point at which the line given by the equation cuts the y axis. This, therefore, means that this is a straight line equation, and can be rearranged in the form y = mx + c , where m is the gradient, and c is the y-axis intercept. Moving 'ax' and 'c' to the other side of the equation, and dividing by 'b', we get the straight line equation y = (-a/b)x - c/b . An example of what this straight line graph may look like can be shown on the whiteboard with example values.

Answered by Dominic E. Maths tutor

7870 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is the probability to obtain exactly 2 heads out of 3 tosses of a fair coin?


Derive from the standard quadratic equation, the form of the quadratic solution


The second and fifth terms of a geometric series are 750 and -6 respectively. Find: (1) the common ratio; (2) the first term of the series; (3) the sum to infinity of the series


Integrate the function x(2x+5)^0.5


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences