Can a projectile of speed 10m/s at an angle of 45° to the horizontal following a path perpendicular to a wall 8m away and 6m high reach beyond the wall? Justify your answer. Take g as 10m/s/s

First draw a rough diagram of what the question describes. The student must work backwards. To answer, they must know the height of the projectile at the wall. To know the height of the projectile, they need the time the projectile has been airborne when at the wall (as using SUVAT elimination would have said). The student calculates this by finding the horizontal component of the projectile, which is invariant, to work out the time the projectile has been airborne when at the wall. Finally with the time calculated, the height can be calculated at the wall using a SUVAT equation. The student can then conclude that the projectile does pass beyond the wall.

Answered by Anton B. Physics tutor

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