Express 4x/(x^2-9) - 2/(x+3) as a single fraction in its simplest form.

To satisfy the condition of substracting two fractions with unlike denominators, a common denominator needs to be found. By recognizing x^2 - 9 = (x-3)(x+3), we can rewrite the question as 4x/(x-3)(x+3) - [2/(x+3)] * [(x-3)/(x-3) ]= [4x-2(x-3)]/[(x+3)(x-3)] = 2(x+3)/(x+3)(x-3) = 2/(x-3)The answer is 2/(x-3).

YC
Answered by Ye C. Maths tutor

6283 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The curve C has the equation (x^2)+4xy-8(y^2)+27=0. Find dy/dx in terms of x and y.


Relative to a fixed origin O, the point A has position vector (8i+13j-2k), the point B has position vector (10i+14j-4k). A line l passes through points A and B. Find the vector equation of this line.


A-level: solve 8cos^2(x)+6sin(x)-6=3 for 0<x<2(pi)


Why does d/dx (tan(x)) = sec^2(x)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning