Express 4x/(x^2-9) - 2/(x+3) as a single fraction in its simplest form.

To satisfy the condition of substracting two fractions with unlike denominators, a common denominator needs to be found. By recognizing x^2 - 9 = (x-3)(x+3), we can rewrite the question as 4x/(x-3)(x+3) - [2/(x+3)] * [(x-3)/(x-3) ]= [4x-2(x-3)]/[(x+3)(x-3)] = 2(x+3)/(x+3)(x-3) = 2/(x-3)The answer is 2/(x-3).

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Answered by Ye C. Maths tutor

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