Find the tangent to the curve y = x^3 - 2x at the point (2, 4). Give your answer in the form ax + by + c = 0, where a, b and c are integers.

y = x3- 2xdy/dx = 3x2 -2plugging in x = 2, therefore gradient = 10using the formula to get the equation of a line y -y1=m(x - x1)substitute y1=4 and x1=2 to get the answer-10x + y + 16 = 0

KS
Answered by Kevalee S. Maths tutor

5452 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is the amplitude and period of y=3sin(5x)?


Intergrate ln(x) with resepct to x


Solve the equation 3^(5x-2)=4^(6-x), and show that the solution can be written in the form log10(a)/log10(b).


What is a Probability Mass Function (PMF)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences