Find the Binomial Expansion of (1-5x)^4.

First I would set up how i was taught using Pascals Triange. As this is to the power of 4 the numbers across will be 1 4 6 4 1.Then I would multiply each number by the correct power of either (-5x) or (1). As I know that if (-5x) is to the power of 2, 1 must be to the power of 2.
This gives me (1 * (1)^4 * (-5x)^0) + (1 * (1)^3 * (-5x)^1) + (1 * (1)^2 * (-5x)^2) + (1 * (1)^1 * (-5x)^3) + (1 * (1)^0 * (-5x)^4).
Anything to the power of 0 is 1 and using this I get the answer1 - 5x + 25x^2 - 125x^3 + 625x^4

MV

Related Maths A Level answers

All answers ▸

Find the exact solution of the following equation: e^(4x-3) = 11


Some videos I've made


∫2x(x+2)^(1/2) dx evaluated from 0->2


a) Simplify 2ln(2x+1) - 10 = 0 b) Simplify 3^(x)*e^(4x) = e^(7)