3 Stacks of coins - A B CAltogether the stacks add up to 130 pence (let's work in pence so its not too confusing). So, A+B+C=130pStack B has 3 times as much money has Stack A. So B = 3AStack C has 2 times as much money as Stack B. So C = 2B. If B = 3A, C = 23A = 6ASo substitute B for 3A and C for 6A into our equation (A+B+C=130) A + 3A + 6A = 130p 10A = 130p A = 13pThe question is asking how much money is in Pile C, so C = 6A C = 613p = 78p