How do you integrate the equation x^2 + 4x + 3 dx? (

Integrating the equations: x² + 4x + 3 dx. To integrate, the method is to look each parts of the equation, e.g. the x² firstly. We would add 1 to the power to get x³ . Then we would divide this by our new power (3) to get 1/3 x³. Next we would look at 4x: We can see that x here is to the power 1. So again as before, we would add 1 to the power to get 4x². Then we divide by the new power to get 2x². Next is the 3: This is interesting as there is no x here, however we can think of the 3 as 3x⁰. This is because x⁰ is equal to 1. So if we are to integrate we would add 1 to the power and divide by the new power as before to get: 3x. When integrating we also have to take into account the constant (c) that we add to our new equation. So our final equation would be 1/3 x³ + 2x²+ 3x + c.