Solve the equation 18x^2-3x=6

First put the equation into the correct form by setting it to 0:18x^2-3x-6=0Look for the common factor in the equation and take it out:3(6x^2-x-2)Using the grid method (which I would show on whiteboard) factor the problem:3(3x-2)(2x+1)=0To find the values of x, set each bracket to equal zero and solve:3x-2=0, 3x=2, x=2/32x+1=0, 2x=-1, x=-1/2There are 2 possible values of x because this is a quadratic equation so looking at the graph of the equation we would be able to see that the graph crosses the x axis at 2 different points

Answered by Grace H. Maths tutor

3881 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve simultaneous equations using the substitution method?


Show that sqrt(20) = 2sqrt(5)


Solve x^2 = 4(x-3)^2


Factorise X^2-X-20


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences