Show that (x + 1)(x + 2)(x + 3) can be written in the form ax3 + bx2 + cx + d where a, b, c and d are positive integers.

lets expand the first two brackets first, so x * x gives x2, x * 2 gives 2x, x * 1 gives x and 1 * 2 = 2. 2x and x are both in terms of x so we add these together to get 3x, giving us the quadratic (x2 + 3x + 2). now we expand this bracket with (x +3). x2 * x = x3x2 * 3 = 3x2 3x * x = 3x2 3x * 3 = 9x 2 * x = 2x 2 * 3 = 6 then when we add all the like terms together we get x3+ 6x2+ 11x + 6 so a=1, b=6, c=11 and d= 6

Answered by Annunzia C. Maths tutor

25106 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the inequality 5x^2 + x - 3 = 1


How do you calculate the hypotenuse of a right angle triangle if the two shorter sides are 6 and 8?


Refer to question taken from Edexcel Maths Paper


Rearrange "(6y-30)/5 = 2x+(12/5)" so it reads "y = ... ". Sketch this line and label where it meets the axes.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences