The curve C has equation f(x) = 4(x^1.5) + 48/(x^0.5) - 8^0.5 for x > 0. (a) Find the exact coordinates of the stationary point of C. (b) Determine whether the stationary point is a maximum or minimum.

Part a:f(x) = 4x1.5 + 48x-0.5 - 80.5Finding the gradient function, f'(x) = 6x0.5 - 24x-1.5At the stationary point, the gradient is zero, so f'(x) = 06x0.5 - 24x-1.5 = 06x2 - 24=0x2 = 4x = 2 is the solution. x = -2 is ignored as C is only defined for x > 0.f(2) = 4(2)1.5 + 48(2)-0.5 - 80.5 = 8(20.5) + 24(20.5) - 2(20.5) = (20.5)*(8+24-2) = 30(20.5) The stationary point is (2, 30(2^0.5)).===========================================Part b:To analyse concavity, we need the rate of change in the gradient, i.e. the second derivate:f''(x) = 3x-0.5 + 36x-2.5f''(2) = 3(2)-0.5 + 36(2)-2.5 > 0This means that at the stationary point, the gradient is increasing. The stationary point is a minimum.

Related Further Mathematics GCSE answers

All answers ▸

(x+4)((x^2) - kx - 5) is expanded and simplified. The coefficient of the x^2 term twice the coefficient of the x term. Work out the value of k.


Solving equations with unknown in both sides


Find the coordinates of the stationary points on the curve y=x^5 -15x^3


The curve C is given by the equation x^4 + x^2y + y^2 = 13. Find the value of dy/dx at the point (-1,3). (A-level)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences