Differentiate the equation y^2 + y = x^3 + 2x

To answer this question you must use implicit differentiation due to there being both x and y terms. Consequently you must differentiate each term individually as you would usually (by multiplying by the power and taking one off the power) but for the y terms due to chain rule the differentiated term must also be multiplied by dy/dx. Consequently the answer becomes: 2y*dy/dx + dy/dx = 3x^2 + 2. The equation must then be rearranged to make dy/dx the subject dy/dx (2y + 1) = 3x^2 + 2 Therefore dy/dx = (3x^2 + 2)/(2y+1)

DW
Answered by Daisy W. Maths tutor

3512 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the Total Area between the curve x^3 -3x^2 +2x and the x-axis, when 0 ≤ x ≤ 2.


Given that sin(x)^2 + cos(x)^2 = 1, show that sec(x)^2 - tan(x)^2 = 1 (2 marks). Hence solve for x: tan(x)^2 + cos(x) = 1, x ≠ (2n + 1)π and -2π < x =< 2π(3 marks)


Given that y = 8x + 2x^-1, find the 2 values for x for which dy/dx = 0


Differentiate 3x^(2)+xy+y^(2)=12 with respect to x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning