The tangent to a point P (p, pi/2) on the curve x=(4y-sin2y)^2 hits the y axis at point A, find the coordinates of this point.

p=4pi2 differentiating with respect to y we have dx/dy = 2(4y-sin2y)(4-2cos2y) substituting in the value of y =pi/2 we have dx/dy = 24pi, which means dy/dx =1/pi24using (y-y_1)=m(x-x_1) we have y-pi/2=1/24pi(x-4pi2) since we know this curve intersects the y axis this means x=0, if we substitute this in y=pi/3

Answered by George N. Maths tutor

3220 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A ball is released from rest at a height of 4m. At what speed does it hit the ground?


4^x - 2^x+1 - 15 = 0


2 log(x + a) = log(16a^6) where a is a positive constant. How do I find x in terms of a?


How do I do this question: A small stone is projected vertically upwards from the point A with speed 11.2 m/s. Find the maximum height above A reached by the stone.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences