If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?

length x width = area (as rectangle)(x-4)(x-5)=12x2-9x+20=12x2-9x+8=0(x-8)(x-1)=0x=8 or x=1 <---- x can't be 1 as we would get negative length and widthx=8

Answered by Simon M. Maths tutor

2836 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify the following fraction - Numerator = 2(8-k) + 4(k-1) Denominator = k^2 - 36


How do you factorise?


5, 11, 21, 35, 53, ... Find the nth term of this sequence.


How do you solve inequalities when you have two inequality symbols in the expression, e.g. 4x - 6 < 14 < 3x + 2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences