If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?

length x width = area (as rectangle)(x-4)(x-5)=12x2-9x+20=12x2-9x+8=0(x-8)(x-1)=0x=8 or x=1 <---- x can't be 1 as we would get negative length and widthx=8

Answered by Simon M. Maths tutor

2961 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you complete a square


Find the possible values of x for x^2 = 36-5x.


A ship is 180 kilometres away from a port P on a bearing of 63 degrees. Another ship is 245 kilometres away from port P on a bearing of 146 degrees. Calculate the distance between the two ships.


Solve the simultaneous equations: 2x + 3y = 5 and 3x + 4y = 12


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences