If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?

length x width = area (as rectangle)(x-4)(x-5)=12x2-9x+20=12x2-9x+8=0(x-8)(x-1)=0x=8 or x=1 <---- x can't be 1 as we would get negative length and widthx=8

Answered by Simon M. Maths tutor

2782 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you factorise quadratic equations by completing the square?


Raya buys a van for £8500 plus VAT at 20%. Raya pays a deposit for the van. She then pays the rest of the cost in 12 equal payments of £531.25 each month. Find the ratio of the deposit Raya pays to the total of the 12 equal payments.


Simplify 2a^3 b × 5a^2 b^3


OPG is a triangle. N is point on OG such that ON : NG = 2 : 3. OP = a, PG = b. Express ON in terms of A and B.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences