Find, using calculus, the x coordinate of the turning point of the curve with equation y=e^3x cos 4

1st step: find the derivative dy/dx of the given equation2nd step: now equate the obtained derivative to 0 because this is precisely the situation in which the graph changes direction (the derivative dy/dx equated to 0 means that the gradient m at that point equals 0. which if you think of logically makes sense to be the gradient at which the direction of the graph changes)3rd step: now just find the value of x from the obtained equation. The value of x you find corresponds to the x-cordinate of the turning point

Answered by Urszula W. Maths tutor

3278 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

(5 + 2(2^0.5))(7 - 3(2^0.5))


How does integration by parts work?


Find the derivative of f where f(x)=a^x.


A curve is defined by the parametric equations; x=(t-1)^3, y=3t-8/(t^2), t~=0. Find dy/dx in terms of t.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences