Let n be an integer greater than 1. Prove that n^2 - 2 - (n-2)^2 is an even number.

To show a number N is even, we must be able to express it in the form N = 2x for some other whole number x. Let's try to manipulate the given expression to see if we can put it in this form. By expanding the squared bracket and gathering like terms (be careful of the minus sign in front of the bracket!), we see that:
n2 - 2 - (n-2)2 = n2 - 2 -n2 +4n - 4 = 4n - 6
Now then, our new aim is to find x such that 4n - 6 = 2x. By dividing both sides of this equation by 2, we see that x = 2n-3. Since 2n - 3 will always be a whole number, we have shown that n2 - 2 - (n-2)2 = 2(2n-3), and so we are done as we have put the expression in the desired form.

SL
Answered by Sam L. Maths tutor

16870 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are 48 girls in a large cheerleading squad. The ratio of girls to boys in this squad is 8:3. How many boys are in the squad?


Rearrange the following to make 'm' the subject. 4(m - 2) = t(5m + 3)


8 pens in a bag, 3 blue, 5 red. 2 taken out at random, without replacement. Probability they are the same colour?


Express f(x) = x^2 + 5x + 9 in the form (x + a)^2 + b, stating the values of a and b.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences