Differentiate x = sinhy with respect to x
x = sinhy=> dx/dy = coshycosh2y - sinh2y = 1=> sqrt(1 + sinh2y) = coshythus dx/dy = sqrt(1 + sinh2y)and dy/dx = 1/sqrt(1 + sinh2y)hence dy/dx = 1/sqrt(1+x2)
AN
Answered by Ayush N. • Further Mathematics tutor
3334 Views
See similar Further Mathematics A Level tutors