A bullet is fired horizontally from a gun at a height of 1.5m at 280m/s. Calculate the time taken for it to hit the ground. A second bullet is fired from an adjacent gun at 370m/s. Calculate the distance it travel before the first bullet hits the ground.

Time for first bullet to hit ground: s = -1.5m, u = 0ms^-1, v = ?, a = -9.81ms^-2, t = ?.s = ut + 1/2(at²)-1.5 = 0 + 1/2(-9.81t²)9.81t²= 1.52 = 3t = sqrt(3/9.81) = 0.55s (2s.f.)Distance travelled by second bullet in 0.55s: s = ?, u = 370ms^-1, v = N/A, a = 0, t = 0.55s.s = ut (since 1/2(at²) = 0)s = 370*0.55 = 204.61...m, approx = 200m (2s.f.)