Solve the simultaneous equations 3x + y = -4 and 3x - 4y = 6

When solving simultaneous equations our goal is always to use the equations given, which each have two unknowns in them, in order to find an equation with only one unknown. In this example, we can see that both equations have 3x on the left hand side, so we can subtract equation 2 from equation 1 to eliminate the x term, giving (3x+y) - (3x-4y) = -4 -6, so 5y = -10 and hence y = -2. From here we can use either equation to find x by substituting the value -2 for y. If we use equation 1, we see that 3x + y = 3x - 2 = -4, hence 3x = -2 and so x = -2/3. For ease of mind we can also check that this agrees with equation 2: 3(-2/3) -4(-2) = -2+8 = 6. We can now be sure that our unknowns x and y satisfy both equations and are -2/3 and -2 respectively.

Answered by Sofya E. Maths tutor

17645 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

I feel really nervous about time pressure in the exam, I don't think I'll finish


Solve the simultaneous equation: x+2y=8 and 2x+y=10 - using a calculator


Factorise and solve x^2 - 8x + 15 = 0


How do I know when to use Sine, Cosine and Tangent


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences