Solve the simultaneous equations 3x + y = -4 and 3x - 4y = 6

When solving simultaneous equations our goal is always to use the equations given, which each have two unknowns in them, in order to find an equation with only one unknown. In this example, we can see that both equations have 3x on the left hand side, so we can subtract equation 2 from equation 1 to eliminate the x term, giving (3x+y) - (3x-4y) = -4 -6, so 5y = -10 and hence y = -2. From here we can use either equation to find x by substituting the value -2 for y. If we use equation 1, we see that 3x + y = 3x - 2 = -4, hence 3x = -2 and so x = -2/3. For ease of mind we can also check that this agrees with equation 2: 3(-2/3) -4(-2) = -2+8 = 6. We can now be sure that our unknowns x and y satisfy both equations and are -2/3 and -2 respectively.

SE
Answered by Sofya E. Maths tutor

21240 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise the quadratic equation: x^2 + 5x + 6 = 0 and hence find the two solutions to the equation.


Raya buys a van for £8500 plus VAT at 20%.Raya pays a deposit for the van. She then pays the rest of the cost in 12 equal payments of £531.25 each month. Find the ratio (in simplest form) of the deposit Raya pays to the total of the 12 equal payments.


How do I expand (x-2)(3x+3) into a quadratic?


How do I factorise a quadratic equation?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning