A curve C is defined by the equation sin3y + 3y*e^(-2x) + 2x^2 = 5, find dy/dx

d(sin3y)/dx= 3cos3y*(dy/dx)d(3ye^(-2x))/dx = -6ye^(-2x) + 3(dy/dx)e^(-2x)d(2x^2)/dx = 4xd(5)/dx = 0so3cos3y(dy/dx) - 6y*e^(-2x) + 3(dy/dx)e^(-2x) + 4x = 0rearrange the equationdy/dx = (6ye^(-2x)-4x)/(3cos3y + 3e^(-2x))

ZZ
Answered by Zhaohui Z. Maths tutor

5345 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Show that (x-2) is a factor of 3x^3 -8x^2 +3x+2


The line AB has equation 5x+3y+3=0. It is parallel to a line with equation y=mx+7. What is m?


Express [1+4(square root)7] /[ 5+ 2(square root)7] in the form m + n (square root)7 , where m and n are integers.


Express 2/P(P-2) in Partial Fractions (C4)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences