A curve C is defined by the equation sin3y + 3y*e^(-2x) + 2x^2 = 5, find dy/dx

d(sin3y)/dx= 3cos3y*(dy/dx)d(3ye^(-2x))/dx = -6ye^(-2x) + 3(dy/dx)e^(-2x)d(2x^2)/dx = 4xd(5)/dx = 0so3cos3y(dy/dx) - 6y*e^(-2x) + 3(dy/dx)e^(-2x) + 4x = 0rearrange the equationdy/dx = (6ye^(-2x)-4x)/(3cos3y + 3e^(-2x))

Answered by Zhaohui Z. Maths tutor

5204 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

differentiate ln( x^2 )


How do you integrate ln(x) with respect to x?


How do I find the equation of the normal to the curve y=x^2 at the point (x1,y1)? Where x1=2 and y1=4 .


Express the equation cosecθ(3 cos 2θ+7)+11=0 in the form asin^2(θ) + bsin(θ) + c = 0, where a, b and c are constants.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences