Given the reaction: H2SO4 + NaOH --> ? + H2O. (a). Work out the salt produced (?) and (b). calculate the pH of the remaining solution when 1.2 g of NaOH and 4.41 g of H2SO4 were added in a 500 ml solution. Of the unreacted H2SO4 95% dissociated.

(a). Firstly, to work out the product, take 2Na⁺ + SO₂^- --> 2Na₂SO₄.(b). To calculate the pH, the equation: pH = -log₁₀([H⁺]) must be used. Therefore we need to find the concentration of hydrogen ions in the resulting solution, [H⁺].Step 1: Work out the molar quantities of the reactants.Looking in a periodic table, the molar mass of S = 32 g mol^-1, H = 1 g mol^-1, Na = 23 g mol^-1, O = 16 g mol^-1. Therefore:H₂SO₄ = 2(1) + 32 + 4(16) = 98 g mol^-1. NaOH = 23 + 16 + 1 = 40 g mol^-1. To work out the molar quantities look at the units or the equation: moles = mass/M_r where M_r is relative molecular mass.for H₂SO₄ = 4.41 g / 98 g mol^-1 = 0.045 mol, for NaOH = 1.2 g / 40 g mol^-1 = 0.030 mol.Step 2: Balance the chemical equation.To do this, count the amount of each atom on each side of the reaction equation then add in the appropriate mole fraction to make sure there is the same amount of each atom on both sides. With the above equation on the LHS: 3 x H, 1 x Na, 5 x O, 1 x S. On the RHS: 2 x H, 2 x Na, 5 x O, 1 x S. Therefore the balanced equation should be:H₂SO₄ + 2NaOH --> Na₂SO₄ + 2H₂O Counting atoms: LHS: 4 x H, 2 x Na, 6 x O, 1 x S. RHS: 4 x H, 2 x Na, 6 x O, 1 x S therefore balanced.Step 3: Calculate concentration of H⁺ ions remaining.Since the mole ratio of H₂SO₄ : NaOH = 1:2, this means that the H₂SO₄ is in excess as only 0.030 mols/2 = 0.015 mols of H₂SO₄ has reacted. Therefore to calculate how many moles of H₂SO₄ are left: 0.045 - 0.015 = 0.030 mols. Since only 95% of the unreacted H₂SO₄ dissociated: 0.030 mols * 0.95 = 0.0285 mols dissociated. Each mol of H₂SO₄ donates 2 mols of H⁺ ions, therefore the mols of H⁺ ions = 0.0285 mols * 2 = 0.057 mols.Therefore the concentration of H⁺ ions in a 500 ml = 0.5 dm³ solution, [H⁺] = 0.057 mols/0.5 dm³ = 0.114 mol dm^-3. Step 4: Calculating the pH of the solution.Using the equation for pH shown above: pH = -log₁₀([H⁺]) we can now work out the pH. pH = -log₁₀(0.114 mol dm^-3) = 0.94