Given y = 4x/(x^2 +5) find dy/dx, writing your answer as a single fraction in its simplest form

This function is fraction so the easiest method is to use the quotient rule (though the product rule can be used). Recall the quotient rule dy/dx = [vu' - uv']/[v^2]Note, u and v refer to the numerator and denominator respectively u' and v' are the first differentials w.r.t x
For this question: u = 4x v = x^2 + 5 hence: u' = 4 v' = 2xApplying the quotient rule: [(x^2 + 5).(4) - (4x).(2x)]/[x^2 + 5]^2Expanding the brackets in the numerator: [4x^2 + 20 - 8x^2]/[x^2 + 5]^2Simplify: dy/dx = [20 -4x^2]/[x^2 + 5]^2No further cancellation or simplification can be done so, the question is finished.

Answered by Laurence C. Maths tutor

3527 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A particle of mass 5kg is held at rests on a slope inclined at 30 degrees to the horizontal. The coefficient of friction for the slope is 0.7, determine whether the particle will move when released.


Solve the simultaneous equations: y-2x-4=0, 4x^2+y^2+20x=0


integrate by parts the equation dy/dx = (3x-4)(2x^2+5).


Differentiate 7(3x^2+7)^(1/3)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences