Solve algebraically: 6a+3b=24, 3a-b=7

Equation 1 : 6a+3b=24Equation 2: 3a-b=7
Rearrange equation 2 to make b the subject:add b to both sides : 3a=7+bminus 7 from both sides: 3a-7=b
Substitute this into Equation 1 : 6a + 3(3a-7)=24
Multiply out the bracket: 6a + 9a - 21 = 24
Simplify:add the a terms together: 15a - 21=24add 21 to both sides: 15a=45divide by 15: a=3
Sub into Equation 2:3(3)-b=7multiply out bracket: 9-b=7add b to both sides: 9=7+bminus 7 from both sides: 2=b
Answer: a=3 b=2

Answered by Emily G. Maths tutor

4180 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

(x+3)(x-4)(x+5) is identical to x^3 +ax^2 -17x+b. Find the value of a and the value of b.


By completing the square, find the coordinates of the turning point of the curve with equation y = x^2 + 10x + 2


The equation of the line L1 is y=3x–2. The equation of the line L2 is 3y–9x+5=0. Show that these two lines are parallel.


Solve 7(k – 3) = 3k – 5


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences