What is the gradient of the curve y = 2x^3 at the point (2,2)?
Firstky differentiate to gain an equation for the gradient.Differentiating gives:dy/dx = 6x2Insert x = 2 into the above equation to find the gradient at that particular point of the curve.When x = 2, dy/dx = 6× 4 = 24Therefore the gradient is 24.