What is the gradient of the curve y = 2x^3 at the point (2,2)?

Firstky differentiate to gain an equation for the gradient.Differentiating gives:dy/dx = 6x2Insert x = 2 into the above equation to find the gradient at that particular point of the curve.When x = 2, dy/dx = 6× 4 = 24Therefore the gradient is 24.

ER
Answered by Emily R. Maths tutor

8262 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve: 2 sin(2x) = (1-sin(x))cos(x) for 0<x<2*Pi and give any values of x, if any, where the equation is not valid


Solve ∫(x+2)/(2x^2+1)^3 dx


A curve has parametric equations x=2t, y=t^2. Find the Cartesian equation of the curve.


Find the equation of the tangent to the curve x^3+yx^2=1 at the point (1,0).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning