How would you solve the simultaneous equations 2x + y = 7 and 3x - y = 8

To solve a pair of simultaneous equations you need to find the values of x and y which are the same for both equations. To do this you should eliminate one of the unknowns - in this instance it can easily be done by adding the two equations together.2x + y + 3x - y = 7 + 8As you can see, the two y's cancel out leaving 5x = 15. You can then divide both sides of this to give x = 3.Now we need to find the value of y when x = 3. To do this you pick one of the original equations to substitute the new value of x into:2 * 3 + y = 76 + y = 7Subtracting 6 from both sides leaves y = 1.Therefore the solution is x = 3 and y = 1.

KH
Answered by Kenna H. Maths tutor

3958 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve algebraically the following if there is a solution: x+y=3 2x+y=5 x^2+y=6


If 2x + y = 13 and 3x - y = 12, what are the values for x and y?


How do you work out the tangent to a circle at a given point on the circle?


Solve: 2x^2 + x = x^2 - 4(x+1)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning