Solve the simultaneous equations 2x+3y=17 and 10x-y=5.

In order to solve the simultaneous equations, you should first get rid of one of the unknowns. In this case, one of the ways to do this is to multiply both sides of the first equation by 5 (2x+3y=17 => 10x+15y=85) and then subtract the second equation from the first one in order to get rid of the x: (10x+15y)-(10x-y)=(85)-(5) => 16y=80 => y=5. Having found y, we can substitute for y=5 in the second equation to find x: 10x-5=5 => 10x=10 => x=1. Hence, we get x=1, y=5.

BA
Answered by Boris A. Maths tutor

3876 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find values for x and y from two simultaneous equations: 2x + y = 5 and 3x + y = 7


Express 50p as a fraction of £4 and give your answer in its simplest form.


Solve the simultaneous equation: 2x - 5y = 9 , x + 6y = -4


Solve the simultaneous equations: 5x + 3y = 41 and 2x + 3y = 20 Do not use trial and error.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning