If I throw a ball vertically upwards with a velocity of 15 m/s and we assume the gravitational acceleration is 10 m/s^2. Draw the distance-time, and velocity-time graphs, how long is the ball in the air before it returns to the point I threw it from?

We will need a SUVAT equations, so first fill in what information we have:S = 0 (the point where the ball returns to the start)U = +15 m/sV = -15 m/s (from graph)A = -10 m/s (important that this is the opposite sign to U)T = We are trying to find thisWe can use :V = U + A*Trearrange:T = (V-U)/A = (-30)/(-10) = 3 Seconds

Answered by Barnaby F. Maths tutor

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