If I throw a ball vertically upwards with a velocity of 15 m/s and we assume the gravitational acceleration is 10 m/s^2. Draw the distance-time, and velocity-time graphs, how long is the ball in the air before it returns to the point I threw it from?
We will need a SUVAT equations, so first fill in what information we have:S = 0 (the point where the ball returns to the start)U = +15 m/sV = -15 m/s (from graph)A = -10 m/s (important that this is the opposite sign to U)T = We are trying to find thisWe can use :V = U + A*Trearrange:T = (V-U)/A = (-30)/(-10) = 3 Seconds
BF
Related Maths A Level answers
All answers ▸How do I integrate ln(x), using integration by parts?
Find values of y such that: log2(11y–3)–log2(3) –2log2(y) = 1
Solve dy/dx= (x√(x^2+3))/e^2y given that y=0 when x=1, giving your answer in the form y = f(x)
At x=3, is the polynomial y= (4/3)x^3 -6x^2 + 11 at a maxima or minima?