What is the oxidation number of Mn in K2MnO4?

The oxidation number of an ion is the same as its charge. We know that the oxidation number of K+ is +1 and the oxidation number of O2- is -2, but we don't know the oxidation number of Mn so let's call that x. There are 2 K+ ions which makes +2 and 4 O2- ions which makes -8 (4*-2) and in K2MnO2 we know the charge of the molecule is neutral so the overall oxidation number must be 0. Therefore +2 (K) + x (Mn) + -8 (O) = 0 which means x = +6 so the oxidation number of Mn is +6 in K2MnO4.

Answered by Alex C. Chemistry tutor

44578 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

What is the difference between empirical and molecular formula?


explain what an enantiomer is


How do I balance redox equations in acidic reactions, without trial and error, using half equations?


The boiling points of ammonia (NH3), fluorine (F2) and bromine (Br2) are -33, -188 and +59 degrees celsius respectively. Explain the differences in these boiling points, including the names of any relevant forces and particles.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences