Work out the equation of the tangent to a circle of centre [0,0] at the point [4,3]

We know that: (1) the radius of the circle to the point [4,3] is perpendicular to the tangent line, (2) if two lines are perpendicular, their gradients are negative reciprocals of each other, and (3) the formula for a straight line is y = mx + c. The radius gradient is equal to 3/4, so the tangent gradient is -4/3. Substituting m, y and x at [4,3] into the straight line formula gives c as 25/3. Therefore, the equation of this tangent line is y = (-4/3)x + (25/3).

Answered by Jamie S. Maths tutor

5767 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise fully 3a^3b + 12a^2b^2 + 9a^5b^3


Simplify 4^2 x 2^4


Write 7/8 as a decimal


Solve the simultaneous equations. (1) 2x + y = 18 (2)x − y = 6


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences