Integrate 3x^4-4x^2+3/x

Firstly, integrate each term individually, starting off with the 3x^4. In order to integrate the index on the x term needs to be raised by 1, and the coefficient of the x should be divided by this new value. In this case; 4+1=5, which is the new index. 3/5 is the new coefficient. Therefore this term equals to 3/5x^5. Doing the same with the next 2 terms and integrating 3/x to 3ln(x) using the integral rule, you will end with the result of 3/5x^5-4/3x^3+3ln(x)+C. Ensure that the "+C" is always included as it contributes towards the marks.

Answered by Muhammad R. Maths tutor

2963 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

We have the curve f(x) = (x^2-5x)(x-1)+ 3x. Sketch the graph y=f(x), making sure to plot the co-ordinates where the curve meets the axes.


If I throw a ball, of mass 2kg, straight up in the air, with velocity 10ms-1, how long until it lands? Assume gravity = 10ms-2


integrate 1/((1-x^2)^0.5) between 0 and 1


Integrate tan (x) with respect to x.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences