Solve the following simultaneous equations: x^2 + y^2 = 5, y - 3x = 1.
Begin by rearranging equation 2 so that it is in the form y = ...
Substitute this into equation 1
Expand the brackets and simplify the equation so that it is in the form Ax^2 + Bx + C = 0
Factorise this quadratic equation to find the two possible solutions for x
Find the respective y values for each value of x
y = 3x +1x^2 + (3x + 1)^2 = 510x^2 + 6x -4 = 0(10x - 4)(x + 1) = 0x = 0.4 or x = -1y = 2.2 or y = -2
DO
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