Answers>Maths>IB>Article

Solve x^2 + 2x = 48 for all values of x

First we need to rearrange so that it's all on one side of the equals sign:x2 + 2x - 48 = 0 Now we have to find what will sum to make the coefficient of x (2) and multiplies together to get -48. So, the factors of 48 are 48 & 1, 24 & 2, 16 & 3, 12 & 4, 8 & 6. As 48 is negative (-) one of the numbers in the pairs must be negative, so in order to make 2 (coefficient of x) the only possible pair is 8 and -6 added together. Therefore; x2 + 2x - 48 = (x + 8)(x - 6) = 0And so; x can be either (-)8 or (+)6 in order to make the equation true.

Answered by Ketan C. Maths tutor

2787 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

Let Sn be the sum of the first n terms of the arithmetic series 2+4+6+... . Find (i) S4 ; (ii) S100 .


find the inverse function of the following: f(x) = 3x-5


Given h(x) = 9^x + 9 and g(x) = 10*3^x, find {x | h(x) < g(x)}.


Find the area under the curve of f(x)=4x/(x^2+1) form x = 0 to x = 2.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences