Answers>Maths>IB>Article

Solve x^2 + 2x = 48 for all values of x

First we need to rearrange so that it's all on one side of the equals sign:x2 + 2x - 48 = 0 Now we have to find what will sum to make the coefficient of x (2) and multiplies together to get -48. So, the factors of 48 are 48 & 1, 24 & 2, 16 & 3, 12 & 4, 8 & 6. As 48 is negative (-) one of the numbers in the pairs must be negative, so in order to make 2 (coefficient of x) the only possible pair is 8 and -6 added together. Therefore; x2 + 2x - 48 = (x + 8)(x - 6) = 0And so; x can be either (-)8 or (+)6 in order to make the equation true.

Answered by Ketan C. Maths tutor

2785 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

Find the cube roots of i in the form a+bi, where a, b are real numbers.


Differentiate x^3 + y^4 = 34 using implicit differentiation


A team of four is chosen from six married couples. If a husband and wife cannot both be on the team, in how many ways can the team be formed?


In a lottery, 6 numbered balls are drawn from a pool of 59. Calculate the probability of scoring a jackpot. There used to be 49 balls in the pool. Calculate by how much the addition of 10 balls has decreased the probability of scoring a jackpot


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences