Calculate the number of moles in a sample of 113.47g of Ca(HCO3)2.

Using the AQA specimen data sheet we see that the RAMs of the following elements areCa = 40.1H = 1.0C = 12.0O = 16.0Therefore the total mass for one mole isCa + 2x(H + C + O+O+O)= 40.1 + 2x(1+12+16+16+16)= 40.1 + 2x61 = 40.1+122=162.1moles = mass / RAM=113.47/162.1 = 0.7 moles