How do I prove (x-2) is a factor of the function f(x) = x^2-4x+4?
First equate the factor to equal 0 then solve:x -2= 0;x = 2;
now plug the number 2 into all the X values:
(2)^2-4(2) + 4 = 8-8 = 0
LC
First equate the factor to equal 0 then solve:x -2= 0;x = 2;
now plug the number 2 into all the X values:
(2)^2-4(2) + 4 = 8-8 = 0